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Chromium(III) hydroxide formation, 2 of 3

Chromium(III) hydroxide formation, 2 of 3. When 0.125M chromium(III) potassium sulfate (KCr(SO4)2) is poured into a beaker with 0.5M sodium hydroxide (NaOH), green chromium(III) hydroxide (Cr(OH)3) is formed. The reaction is KCr(SO4)2 + NaOH -> Cr(OH)3 + KNaSO4 + Na2SO4.
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Title: Chromium(III) hydroxide formation, 2 of 3
Caption: Chromium(III) hydroxide formation, 2 of 3. When 0.125M chromium(III) potassium sulfate (KCr(SO4)2) is poured into a beaker with 0.5M sodium hydroxide (NaOH), green chromium(III) hydroxide (Cr(OH)3) is formed. The reaction is KCr(SO4)2 + NaOH -> Cr(OH)3 + KNaSO4 + Na2SO4.
Credit: Album / Turtle Rock Scientific/Science Source
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Image size: 3424 × 5153 px | 50.5 MB
Print size: 29.0 × 43.6 cm | 1348.0 × 2028.7 in (300 dpi)
Keywords: ALUM • BEAKER • CHEMICAL • CHEMISTRY • CHROME • CHROMIUM • CR • CROH3 • HYDROXIDE • KCRSO42 • METAL • NAOH • POTASSIUM • PRECIPITATE • REACTION • SALT • SODIUM • SULFATE • SULPHATE