alb10700668

Chromium(III) hydroxide formation, 2 of 3

Chromium(III) hydroxide formation, 2 of 3. When 0.125M chromium(III) potassium sulfate (KCr(SO4)2) is poured into a beaker with 0.5M sodium hydroxide (NaOH), green chromium(III) hydroxide (Cr(OH)3) is formed. The reaction is KCr(SO4)2 + NaOH -> Cr(OH)3 + KNaSO4 + Na2SO4.
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Title:
Chromium(III) hydroxide formation, 2 of 3
Caption:
Chromium(III) hydroxide formation, 2 of 3. When 0.125M chromium(III) potassium sulfate (KCr(SO4)2) is poured into a beaker with 0.5M sodium hydroxide (NaOH), green chromium(III) hydroxide (Cr(OH)3) is formed. The reaction is KCr(SO4)2 + NaOH -> Cr(OH)3 + KNaSO4 + Na2SO4.
Credit:
Album / Turtle Rock Scientific/Science Source
Releases:
Model: No - Property: No
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Image size:
3424 x 5153 px | 50.5 MB
Print size:
29.0 x 43.6 cm | 11.4 x 17.2 in (300 dpi)
Keywords:
ALUM BEAKER CHEMICAL CHEMISTRY CHROME CHROMIUM CR CROH3 HYDROXIDE KCRSO42 METAL NAOH POTASSIUM PRECIPITATE REACTION SALT SODIUM SULFATE SULPHATE